翻转二叉树

1.题目

翻转一棵二叉树。

示例:

输入:

       4
     /   \
  2     7
 / \   / \
1   3 6   9

输出:
4
/
7 2
/ \ /
9 6 3 1

2.分析

使用深度遍历即可,左右子字点互换即可。

3.代码

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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode invertTree(TreeNode root) {
if(root == null){
return root;
}
TreeNode temp = root.left;
root.left = root.right;
root.right = temp;
root.left=invertTree(root.left);
root.right=invertTree(root.right);
return root;
}
}